If Statement With True Value That Contains A Colon
How can I use an IF statement with a true value being a variable that has a colon in it? The colon in the true value variable is being taken as the delimiter for the false value.
The only solution I came up with was some hackery to use STRREPLACE to replace the : with a % before the IF statement and then use STRREPLACE
again after to change the % back to a :.
i.e.:
Set(dialexts=${STRREPLACE(dialexts,:,%)});
Set(dialexts=${IFTIME(8:00-22:00?${dialexts}&${MBDR}:${dialexts})});
Set(dialexts=${STRREPLACE(dialexts,%,:)});
Is there no better alternative?
Cheers, b.
2 thoughts on - If Statement With True Value That Contains A Colon
Le 13/09/2019 à 14:03, Brian J. Murrell a écrit :
Escape it with \
—
Daniel
—
Tried that. It doesn’t work.
Cheers, b.